Answer
$\frac{z}{6}$
Work Step by Step
$\frac{3z^{2}+z}{18z+6}=\frac{z(3z+1)}{6(3z+1)}=\frac{z}{6}\times\frac{(3z+1)}{(3z+1)}=\frac{z}{6}\times1=\frac{z}{6}$
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