Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 86



Work Step by Step

Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ or the cube of a binomial, the given expression, $ (x+3y)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (x)^3+3(x)^2(3y)+3(x)(3y)^2+(3y)^3 \\\\= (x)^3+3(x^2)(3y)+3(x)(9y^2)+(27y^3) \\\\= x^3+9x^2y+27xy^2+27y^3 .\end{array}
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