Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 305: 76



Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ [(3m-2)+p]^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (3m-2)^2+2(3m-2)(p)+(p)^2 \\\\= (3m-2)^2+2p(3m-2)+p^2 \\\\= (3m-2)^2+6mp-4p+p^2 \\\\= [(3m)^2+2(3m)(-2)+(-2)^2]+6mp-4p+p^2 \\\\= 9m^2-12m+4+6mp-4p+p^2 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.