Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 305: 51

Answer

$9a^{2}-4c^{2}$

Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $(3a+2c)(3a-2c)=(3a)^{2}-(2c)^{2}=3^{2}a^{2}-2^{2}c^{2}=9a^{2}-4c^{2}$.
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