Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 305: 73

$3w^2-6wz+\dfrac{1}{4}wz-\dfrac{1}{2}z^2$

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the product of the binomials in the given expression, $ \left( 3w+\dfrac{1}{4}z \right)( w-2z ) ,$ is \begin{array}{l}\require{cancel} 3w(w)+3w(-2z )+\dfrac{1}{4}z(w)+\dfrac{1}{4}z(-2z) \\\\= 3w^2-6wz+\dfrac{1}{4}wz-\dfrac{1}{2}z^2 .\end{array}