## Intermediate Algebra (12th Edition)

$16n^{2}-24nm+9m^{2}$
From Page 302, we know that the square of a binomial difference $x-y$ is given by the following equation: $(x-y)^{2}=x^{2}-2xy+y^{2}$ Therefore, $(4n-3m)^{2}=(4n)^{2}-2(4n)(3m)+(3m)^{2}=4^{2}n^{2}-24nm+3^{2}m^{2}=16n^{2}-24nm+9m^{2}$.