Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 305: 75



Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ [(5x+1)+6y]^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (5x+1)^2+2(5x+1)(6y)+(6y)^2 \\\\= (5x+1)^2+12y(5x+1)+36y^2 \\\\= (5x+1)^2+60xy+12y+36y^2 \\\\= [(5x)^2+2(5x)(1)+(1)^2]+60xy+12y+36y^2 \\\\= 25x^2+10x+1+60xy+12y+36y^2 .\end{array}
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