Answer
$-32x^{25}$
Work Step by Step
According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number).
Therefore, $(-2x^{5})^{5}=(-1\times2\times x^{5})^{5}=(-1)^{1\times5}\times2^{1\times5}\times x^{5\times5}=(-1)^{5}\times2^{5}\times x^{25}=-1\times32\times x^{25}=-32x^{25}$.
