## Intermediate Algebra (12th Edition)

$\frac{11}{30}$
According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $5^{-1}+6^{-1}=\frac{1}{5}+\frac{1}{6}=\frac{1\times6}{5\times6}+\frac{1\times5}{6\times5}=\frac{6+5}{30}=\frac{11}{30}$.