Answer
$\frac{5}{8}$
Work Step by Step
According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$.
Therefore, $2^{-1}+8^{-1}=\frac{1}{2}+\frac{1}{8}=\frac{1\times4}{2\times4}+\frac{1}{8}=\frac{4+1}{8}=\frac{5}{8}$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 277: 54
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