Answer
$-\frac{1}{32x^{5}}$
Work Step by Step
According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$.
Therefore, $(-2x)^{-5}=\frac{1}{(-2x)^{5}}=\frac{1}{(-2)^{5}x^{5}}=\frac{1}{-32x^{5}}=-\frac{1}{32x^{5}}$.
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