Answer
$-\frac{1}{12}$
Work Step by Step
According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$.
Therefore, $6^{-1}-4^{-1}=\frac{1}{6}-\frac{1}{4}=\frac{1\times4}{6\times4}-\frac{1\times6}{4\times6}=\frac{4-6}{24}=\frac{-2}{24}=-\frac{2}{24}=-\frac{1}{12}$.