Answer
49
Work Step by Step
According to the quotient rule for exponents, $\frac{a^{m}}{a^{n}}=a^{m-n}$ (where $a\ne0$).
Therefore, $\frac{7}{7^{-1}}=\frac{7^{1}}{7^{-1}}=7^{1-(-1)}=7^{2}=49$.
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