## Intermediate Algebra (12th Edition)

$x$
We are given that $xy^{0}=0$ (where $y\ne0$). However, we know that $a^{0}=1$ (as long as $a$ is a nonzero real number). In other words, we know that any nonzero number raised to a power of 0 will equal 1. Therefore, $xy^{0}=x\times 1=x$.