Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 276: 35


a. B. $\frac{1}{25}$ b. D. $-\frac{1}{25}$ c. B. $\frac{1}{25}$ d. D. $-\frac{1}{25}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, a. $5^{-2}=\frac{1}{5^{2}}=\frac{1}{5\times5}=\frac{1}{25}$ b. $-5^{-2}=-\frac{1}{5^{2}}=-\frac{1}{5\times5}=-\frac{1}{25}$ c. $(-5)^{-2}=\frac{1}{(-5)^{2}}=\frac{1}{-5\times-5}=\frac{1}{25}$ d. $-(-5)^{-2}=-\frac{1}{(-5)^{2}}=-\frac{1}{-5\times-5}=-\frac{1}{25}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.