## Intermediate Algebra (12th Edition)

According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1. Therefore, $-8^{0}-k^{0}=-(8^{0})-(k^{0})=-(1)-(1)=-1-1=-2$. Recall that the bases of the exponents are 8 and k, respectively, and not -8 and –k.