Answer
0
Work Step by Step
According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1.
Therefore, $-3^{0}+3^{0}=-(3^{0})+3^{0}=-(1)+1=-1+1=0$.
Recall that the base of the first exponent is 3 and not -3.