Answer
$18x^{3}y^{8}$
Work Step by Step
We are given the expression $(2x^{2}y^{5})(9xy^{3})$. Before applying the product rule for exponents, we can group like terms.
$(2x^{2}y^{5})(9xy^{3})=(2\times9)(x^{2}\times x)(y^{5}\times y^{3})=(18)(x^{2+1})(y^{5+3})=(18)(x^{3})(y^{8})=18x^{3}y^{8}$.
