Answer
a. D. 8
b. E. -8
c. B. 1
d. B. 1
Work Step by Step
According to page 267, $a^{0}=1$ (where $a$ is a nonzero real number). In other words, we know that any nonzero real number raised to a power of 0 will equal 1.
Therefore,
a. $8x^{0}=8\times1=8$
b. $-8x^{0}=-8\times1=-8$
c. $(8x)^{0}=8^{0}x^{0}=1\times1=1$
d. $(-8x)^{0}=-8^{0}x^{0}=1\times1=1$
