## Intermediate Algebra (12th Edition)

$\left\{ x| x=-\dfrac{10}{9} \right\}$
Using the properties of equality, the given equation, $8x-(x+3)=-(2x+1)-12 ,$ is equivalent to \begin{array}{l}\require{cancel} 8x-x-3=-2x-1-12 \\\\ 8x-x+2x=-1-12+3 \\\\ 9x=-10 \\\\ x=-\dfrac{10}{9} .\end{array} Hence, the solution is $\left\{ x| x=-\dfrac{10}{9} \right\} .$