Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 44


$\left\{ x| x=-\dfrac{10}{9} \right\} $

Work Step by Step

Using the properties of equality, the given equation, $ 8x-(x+3)=-(2x+1)-12 ,$ is equivalent to \begin{array}{l}\require{cancel} 8x-x-3=-2x-1-12 \\\\ 8x-x+2x=-1-12+3 \\\\ 9x=-10 \\\\ x=-\dfrac{10}{9} .\end{array} Hence, the solution is $ \left\{ x| x=-\dfrac{10}{9} \right\} .$
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