## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 38

#### Answer

$\left( -6,8 \right)$

#### Work Step by Step

Since for any $a\gt0$, $|x|\lt a$ implies $-a\lt x\lt a,$ then the given inequality, $|x-1|\lt7 ,$ is equivalent to \begin{array}{l}\require{cancel} -7\lt x-1\lt7 .\end{array} Using the properties of inequality, then \begin{array}{l}\require{cancel} -7+1\lt x-1+1\lt7+1 \\\\ -6\lt x\lt8 .\end{array} Hence, the solution is the interval $\left( -6,8 \right) .$

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