Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 37


$\left\{ x| x=-\dfrac{5}{2} \right\}$

Work Step by Step

Using the properties of equality, the given equation, $ -(x+4)+2=3x+8 ,$ is equivalent to \begin{array}{l}\require{cancel} -x-4+2=3x+8 \\\\ -x-3x=8-2+4 \\\\ -4x=10 \\\\ x=\dfrac{10}{-4} \\\\ x=-\dfrac{\cancel{10}^5}{\cancel{4}^2} \\\\ x=-\dfrac{5}{2} .\end{array} Hence, the solution is $ \left\{ x| x=-\dfrac{5}{2} \right\} .$
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