Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 28


$\left\{ x| x=24 \right\}$

Work Step by Step

Multiplying both sides by the $LCD= 12 $, the given equation, $ \dfrac{x}{4}-\dfrac{2x}{3}=-10 ,$ is equivalent to \begin{array}{l}\require{cancel} 3(x)-4(2x)=12(-10) \\\\ 3x-8x=-120 \\\\ -5x=-120 \\\\ x=\dfrac{-120}{-5} \\\\ x=24 .\end{array} Hence, the solution is $ \left\{ x| x=24 \right\} .$
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