Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 19



Work Step by Step

We are given the equation $\frac{2}{3}x+8=\frac{1}{4}x$. In order to solve, first multiply all terms by 12 (the greatest common denominator of all terms). $8x+96=3x$ Subtract 8x from both sides. $-5x=96$ Divide by -5. $x=-\frac{96}{5}$
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