Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Summary Exercises - Reviewing a Chapter - Solving Linear and Absolute Value Equations and Inequalities - Page 122: 23



Work Step by Step

We are given the equation $\frac{3}{5}x-\frac{1}{10}=2$. In order to solve, multiply all terms by 10 (the greatest common denominator of all terms). $6x-1=20$ Add 1 to both sides. $6x=21$ Divide by 6. $x=\frac{21}{6}=\frac{21\div3}{6\div3}=\frac{7}{2}$
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