Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Appendix - Synthetic Division - Exercises - Page 646: 5

Answer

$4m-1$

Work Step by Step

Setup: Dividing with $m-k$, place k as the top left entry. List coefficients of the numerator (0 for missing powers) in the first row. Copy the leading coefficient to the bottom row, same column. $\begin{array}{rrr} {-5 )} &{4}&{19}&{-5}\\ { } &{ }&{ } &{ }\\ \hline &{4 }&{ } &{ }\end{array}$ Fill the next entries, column by column: Middle row: k$\times$(previous bottom row entry) Bottom row: add the two entries above. Repeat. $\begin{array}{rrr} {-5 )} &{4}&{19}&{-5}\\ { } &{ }&{-20} &{ 5 }\\ \hline &{4 }&{-1 } &{0 }\end{array}$ Interpret result: Q(x) is the quotient, R(x) the remainder. $Q(m)=4m-1,\quad R(m)=0$ $\displaystyle \frac{P(m)}{D(m)}=Q(m)+\frac{R(m)}{D(m)}$ $\displaystyle \frac{4m^{2}+19m-5}{m+5}=4m-1$
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