Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Appendix - Synthetic Division - Exercises - Page 646: 35

Answer

$P(-4)=0$

Work Step by Step

Substituting $x=-4$ in $ P(x)=2x^2+5x-12 $, results to \begin{align*} P(-4)&= 2(-4)^2+5(-4)-12 \\&= 2(16)+5(-4)-12 \\&= 32-20-12 \\&= 0 .\end{align*} Hence, $P(-4)=0$.
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