Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Appendix - Synthetic Division - Exercises - Page 646: 4

Answer

$x-7$

Work Step by Step

Setup: Dividing with $x-k$, place k as the top left entry. List coefficients of the numerator (0 for missing powers) in the first row. Copy the leading coefficient to the bottom row, same column. $\begin{array}{rrr} {-3 )} &{1}&{-4}&{21}\\ { } &{ }&{ } &{ }\\ \hline &{1 }&{ } &{ }\end{array}$ Fill the next entries, column by column: Middle row: k$\times$(previous bottom row entry) Bottom row: add the two entries above. Repeat. $\begin{array}{rrr} {-3 )} &{1}&{-4}&{21}\\ { } &{ }&{-3 } &{21 }\\ \hline &{1 }&{ -7} &{0 }\end{array}$ Interpret result: Q(x) is the quotient, R(x) the remainder. $Q(x)=x-7,\quad R(x)=0$ $\displaystyle \frac{P(x)}{D(x)}=Q(x)+\frac{R(x)}{D(x)}$ $\displaystyle \frac{x^{2}-4x-21}{x+3}=x-7$
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