Answer
See below.
Work Step by Step
Because
$\begin{bmatrix}
1& 1 \\
1& 1\\
\end{bmatrix} \begin{bmatrix}
c \\
-c\\
\end{bmatrix}
=\begin{bmatrix}
0 \\
0\\
\end{bmatrix} =0 \begin{bmatrix}
c \\
-c\\
\end{bmatrix} $
and
$\begin{bmatrix}
1& 1 \\
1& 1\\
\end{bmatrix} \begin{bmatrix}
c \\
c\\
\end{bmatrix}
=\begin{bmatrix}
2c \\
2c\\
\end{bmatrix} =2 \begin{bmatrix}
c \\
c\\
\end{bmatrix} $
we have proved what we wanted to.