Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - Review Exercises - Page 221: 15

Answer

$$ 0=(0,0,0). $$ $$-u=(-a,-b,-c).$$

Work Step by Step

The zero vector of the vector space $R^3$ is given by $$ 0=(0,0,0). $$ Let $u$ be an vector in $R^3$ such that $$u=(a,b,c).$$ Now, the additive inverse of $u$ is given by $$-u=(-a,-b,-c).$$
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