Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - Review Exercises - Page 221: 14

Answer

$$ 0=0+0x+0x^2+0x^3+0x^4+0x^5+0x^6+0x^7+0x^8. $$ $$-u=-a_0-a_1x-a_2x^2-a_3x^3-a_4x^4-a_5x^5-a_6x^6-a_7x^7-a_8x^8.$$

Work Step by Step

The zero vector of the vector space $P_8$ is given by $$ 0=0+0x+0x^2+0x^3+0x^4+0x^5+0x^6+0x^7+0x^8. $$ Let $u$ be an vector in $P_8$ such that $$u=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+a_7x^7+a_8x^8.$$ Now, the additive inverse of $u$ is given by $$-u=-a_0-a_1x-a_2x^2-a_3x^3-a_4x^4-a_5x^5-a_6x^6-a_7x^7-a_8x^8.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.