Answer
$v$ can not be a linear combination of $u_1$, $u_2$ and $u_3$.
Work Step by Step
Suppose the following linear combination
$$(4,-13,-5,-4)=a(1,-2,1,1)+b(-1,2,3,2)+c(0,-1,-1,-1), \quad a,b,c\in R.$$
Which yields the following system of equations
\begin{align*}
a-b&=4\\
-2a+2b-c&=-13\\
a+3b-c&=-5\\
a+2b-c&=-4.
\end{align*}
One can see that the above system is inconsistent and hence $v$ can not be a linear combination of $u_1$, $u_2$ and $u_3$.
