## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.3 Factoring Trinomials of the Type ax2+bx+c - 5.3 Exercise Set - Page 326: 54

#### Answer

$-(4x+7)(4x+1)$

#### Work Step by Step

Factoring the negative $GCF= -1 ,$ the given expression is equivalent to \begin{array}{l}\require{cancel} -16x^2-32x-7 \\\\= -(16x^2+32x+7) .\end{array} Using the factoring of trinomials in the form $ax^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} -(16x^2+32x+7) \end{array} has $ac= 16(7)=112$ and $b= 32 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ 28,4 \right\}.$ Using these $2$ numbers to decompose the middle term of the trinomial expression above results to \begin{array}{l}\require{cancel} -(16x^2+28x+4x+7) .\end{array} Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} -[(16x^2+28x)+(4x+7)] .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} -[4x(4x+7)+(4x+7)] .\end{array} Factoring the $GCF= (4x+7)$ of the entire expression above results to \begin{array}{l}\require{cancel} -[(4x+7)(4x+1)] \\\\= -(4x+7)(4x+1) .\end{array}

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