Answer
$(n+5)(7n-1)$
Work Step by Step
Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to
\begin{array}{l}\require{cancel}
7n^2+35n-n-5
\\\\=
(7n^2+35n)-(n+5)
.\end{array}
Factoring the $GCF$ in each group results to
\begin{array}{l}\require{cancel}
7n(n+5)-(n+5)
.\end{array}
Factoring the $GCF=
(n+5)
$ of the entire expression above results to
\begin{array}{l}\require{cancel}
(n+5)(7n-1)
.\end{array}