# Chapter 5 - Polynomials and Factoring - 5.3 Factoring Trinomials of the Type ax2+bx+c - 5.3 Exercise Set - Page 326: 50

$(5a-2)(2a-1)$

#### Work Step by Step

Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} 10a^2-4a-5a+2 \\\\= (10a^2-4a)-(5a-2) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} 2a(5a-2)-(5a-2) .\end{array} Factoring the $GCF= (5a-2)$ of the entire expression above results to \begin{array}{l}\require{cancel} (5a-2)(2a-1) .\end{array}

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