## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.3 Factoring Trinomials of the Type ax2+bx+c - 5.3 Exercise Set - Page 326: 13

#### Answer

$(2x+3)(3x+4)$

#### Work Step by Step

Using the factoring of trinomials in the form $ax^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} 6x^2+17x+12 \end{array} has $ac= 6(12)=72$ and $b= 17 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ 9,8 \right\}.$ Using these $2$ numbers to decompose the middle term of the trinomial expression above results to \begin{array}{l}\require{cancel} 6x^2+9x+8x+12 .\end{array} Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (6x^2+9x)+(8x+12) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} 3x(2x+3)+4(2x+3) .\end{array} Factoring the $GCF= (2x+3)$ of the entire expression above results to \begin{array}{l}\require{cancel} (2x+3)(3x+4) .\end{array}

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