## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(3x-2)(x+1)$
Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} 3x^2-2x+3x-2 \\\\= (3x^2-2x)+(3x-2) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} x(3x-2)+(3x-2) .\end{array} Factoring the $GCF= (3x-2)$ of the entire expression above results to \begin{array}{l}\require{cancel} (3x-2)(x+1) .\end{array}