Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.3 Factoring Trinomials of the Type ax2+bx+c - 5.3 Exercise Set - Page 326: 46

Answer

$(3x-2)(x+1)$

Work Step by Step

Grouping the first and second terms and the third and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} 3x^2-2x+3x-2 \\\\= (3x^2-2x)+(3x-2) .\end{array} Factoring the $GCF$ in each group results to \begin{array}{l}\require{cancel} x(3x-2)+(3x-2) .\end{array} Factoring the $GCF= (3x-2) $ of the entire expression above results to \begin{array}{l}\require{cancel} (3x-2)(x+1) .\end{array}
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