Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 311: 70



Work Step by Step

The given expression, $ (w^2y+yz-w^2)+(w^2-2w^2y+wz) ,$ simplifies to \begin{array}{l}\require{cancel} w^2y+yz-w^2+w^2-2w^2y+wz \\\\= (w^2y-2w^2y)+yz+(-w^2+w^2)+wz \\\\= -w^2y+yz+0w^2+wz \\\\= -w^2y+yz+wz .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.