Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 311: 62

Answer

$(5g-1)(4g^2-5)$

Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ 20g^3+5-4g^2-25g ,$ is \begin{array}{l} 20g^3-4g^2-25g+5 \\\\= (20g^3-4g^2)-(25g-5) \\\\= 4g^2(5g-1)-5(5g-1) \\\\= (5g-1)(4g^2-5) .\end{array}
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