Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 311: 69



Work Step by Step

The given expression, $ (3x^2-x-3)-(-x^2-6x+10) ,$ simplifies to \begin{array}{l}\require{cancel} 3x^2-x-3+x^2+6x-10 \\\\= (3x^2+x^2)+(-x+6x)+(-3-10) \\\\= 4x^2+5x-13 .\end{array}
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