# Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 311: 65

$\dfrac{3}{25}$

#### Work Step by Step

The given expression, $\dfrac{2}{5}\div\dfrac{10}{3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2}{5}\cdot\dfrac{3}{10} \\\\= \dfrac{2(3)}{5(10)} \\\\= \dfrac{\cancel{2}(3)}{5(\cancel{2}\cdot5)} \\\\= \dfrac{3}{25} .\end{array}

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