## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set: 68

#### Answer

$a^{7}b^{7}c^{3}$

#### Work Step by Step

The given expression, $(a^2b^3c)(a^5b^4c^2) ,$ simplifies to \begin{array}{l}\require{cancel} a^{2+5}b^{3+4}c^{1+2} \\\\= a^{7}b^{7}c^{3} .\end{array}

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