Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set: 67

Answer

$\dfrac{y^{4}}{2x}$

Work Step by Step

The given expression, $ (2xy^{-4})^{-1} ,$ simplifies to \begin{array}{l}\require{cancel} 2^{-1}x^{-1}y^{-4(-1)} \\\\= 2^{-1}x^{-1}y^{4} \\\\= \dfrac{y^{4}}{2^{1}x^{1}} \\\\= \dfrac{y^{4}}{2x} .\end{array}
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