Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 7

Answer

$\text{slope: } \dfrac{1}{4} ,\\\text{a point on the line: } (5,3)$

Work Step by Step

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the given equation, $ y-3=\dfrac{1}{4}(x-5) $, has the following characteristics: \begin{array}{l} \text{slope: } \dfrac{1}{4} ,\\\text{a point on the line: } (5,3) .\end{array}
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