Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 42



Work Step by Step

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the line with the given slope equal to $ -\dfrac{1}{5} $ and with the given point $\left( -2,1 \right)$ is \begin{array}{l} y-1=-\dfrac{1}{5}(x-(-2)) \\\\ y-1=-\dfrac{1}{5}(x+2) \\\\ y-1=-\dfrac{1}{5}x-\dfrac{2}{5} \\\\ y=-\dfrac{1}{5}x-\dfrac{2}{5}+1 \\\\ y=-\dfrac{1}{5}x-\dfrac{2}{5}+\dfrac{5}{5} \\\\ y=-\dfrac{1}{5}x+\dfrac{3}{5} .\end{array}
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