# Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 50

$y-4=-3(x-1)$

#### Work Step by Step

Using the properties of equality, the given linear equation, $3x+y=5$ is equivalent to \begin{array}{l} y=-3x+5 .\end{array} Using $y=mx+b$ or the Slope-Intercept form where $m$ is the slope, then the slope of the given line is $-3$. Since parallel lines have the same slope, then the needed linear equation has the same slope and it passes through the given point $( 1,4 )$. Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the needed line is \begin{array}{l} y-4=-3(x-1) .\end{array}

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