Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 24



Work Step by Step

RECALL: (1) The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. (2) The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $b$ is the y-coordinate of the line's y-intercept. (3) Parallel lines have equal slopes. (4) Perpendicular lines have slopes whose product is $-1$. The line is parallel to $y=\frac{1}{2}x+6$. Since the slope of this line is $\frac{1}{2}$, then the slope of the line parallel to it is also $\frac{1}{2}$. Using the given point on the line $(0, -1)$ (which is the y-intercept) and the slope $\frac{1}{2}$, the equation of the line in slope-intercept form is: $y=\frac{1}{2}x+(-1) \\y=\frac{1}{2}x-1$
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