Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 54



Work Step by Step

Using the properties of equality, the given linear equation, $ 5x-6y=4 $ is equivalent to \begin{array}{l} -6y=-5x+4 \\\\ y=\dfrac{-5}{-6}x+\dfrac{4}{-6} \\\\ y=\dfrac{5}{6}x-\dfrac{2}{3} .\end{array} Using $y=mx+b$ or the Slope-Intercept form where $m$ is the slope, then the slope of the given line is $ \dfrac{5}{6} $. Since parallel lines have the same slope, then the needed linear equation has the same slope and it passes through the given point $( 3,-4 )$. Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the needed line is \begin{array}{l} y-(-4)=\dfrac{5}{6}(x-3) \\\\ y+4=\dfrac{5}{6}(x-3) .\end{array}
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