## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\text{slope: } -\dfrac{2}{3} ,\\\text{a point on the line: } (-8,4)$
Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the given equation, $y-4=-\dfrac{2}{3}(x+8)$, has the following characteristics: \begin{array}{l} \text{slope: } -\dfrac{2}{3} ,\\\text{a point on the line: } (-8,4) .\end{array}