Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 88



Work Step by Step

Converting to exponential form, the solution to the given logarithmic equation, $ \log_2{x}=-1 ,$ is \begin{array}{l}\require{cancel} x=2^{-1} \\\\ x=\dfrac{1}{2^1} \\\\ x=\dfrac{1}{2} .\end{array}
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